This is due to format specifier
%char. It is not a valid format specifier, there is no such thing as
%char that C understands.
Make a habit of standard library reading man pages of the functions that you are planning to use. For example,
scanf. Read through Conversions section of that man page. That will guide you about what format specifiers are to be used with
Look at the variable there:
char, it can only hold one character.
To store a name, I assume that you need more than one
char. So you might want to use an array of characters.
So, change it to:
char name[MAX_LENGTH_NAME]; //MAX_LENGTH_NAME can be a macro set to some
value, example 32?
And change your
scanf() call for worker name to,
scanf("%s", name); // Note: `&` is gone here!
Getting the return values from
scanf(), and adding some error handling for unexpected return will save you a lot of pain going ahead.
printf() says, its a program to calculate something for 10 workers,
This loops for 11 iterations, not 10. I hope you aren't the 11th worker :-).
Change it to
for(i = 0; i < 10; i++).
conio.h is non-standard. If you are developing on a platform that mandates you using this header, you may want consider switching to a better development environment. For example, a linux machine with a bash terminal and a standard gcc compiler.
void main is bad, use
int main(void) instead. To know more on why, read What should main() return?
Irrelevant: GUI Design and what messages you throw up on console are very crucial going ahead.
He is strictly masculine :D Aren't there any women workers around? It could be way better if you start printing the name instead of